Friday, September 28, 2007

MSA 2.5

Questions and Comments:

Crossing the Line

9 comments:

Anonymous said...

I was confused here with multiplication of real numbers. I was able to multipy the real numbers, but on some of the problems, the numbers were all run together. At the time, I did not know that they were supposed to be simplified with the distrubutive
property. Then, after I simplfied, I solved the problem both ways, and came up with two different answers. I dont know if I multiplied or added wrong, or if I just simplified wrong...-A.L.

Anonymous said...

1. Finding a solution on an equation helps you on a coordinate graph because? Why does this help on a coordinate? Wouldn’t you just need the formula, and not the solution, because you could make the graph by the intervals? Could someone clear this up for me?
The problem was class work, problem 3.3 on page 40. It was just something I was wondering about when I was doing the problems.

Anonymous said...

3. This is not a question out of the book, but about the calculator that we did in class. How do you know what intervals the graphs are going by without looking at the table or anything else? I know you can set it to what you want the intervals to be, but one day in class, someone made a graph, and everyone was trying to mimic the graph, but I didn’t get how to do it.
JW

Anonymous said...

SV to AL
This is a 7th grader in ms. leckmans class and you posted in the wrong section so you need to post in the mcdl section!!!!

Anonymous said...

BJ
i was really confused in the ACES #21. what i need help with was on the table and how to plot the data when the book is talking about the wind direction.

Anonymous said...

i had trouble trying to solve #21 in the aces. we went over it in class but i still didn't get it at all. i know mrs.L said to forget about the problem but i wanted to know if anyone did solve the problem in some way that is easier to understand. if not its ok because we were supposed to forget about is. i just couldn't get it out of my mind until i found out if it was possible.

Anonymous said...

J.W.,
I might be able to help you, but I think the equation can help you on a coordinate graph because it helps you locate the coefficient, and the x and y axis.

B.B.

Anonymous said...

EMK to JW (J Dub)
You pretty much have to look at the table to know what the intervals are or on the graphing calculator press the left, right, up and down buttons to get what the intervals go by.

Anonymous said...

BJ to (no name)the person asking about how an equation helps and coorinate.
lets use the equation from the problem.(y=5x-3)K. x would be whatever # you start with. lets start with 2. the x-coordinate will be 2. solve the equation for the y-coordinate. 5x2=10. 10-3=7, so the y-coordinate will be 7. your coordinate points would be (2,7)this is how an equation helps you find your coorinate points.