This quote has evolved over time into the quote you see above. The orginal Shakespeare Quote is:
"Though this be madness, yet there is method in 't."
--From Hamlet (II, ii, 206)
Friday, September 28, 2007
MCDL 2.5
Questions and Comments:
Multiplication of Real Numbers
11 comments:
Anonymous
said...
d.c.
is this chapter i have trouble simplifing the variable expression. for example if it gives you 5(-a)(-a)(-a) i am not sure what the steps for this is.
The other problem i have stuggled with is adding sutracting, multiplying and dividing negitive integers. Like in problem #27 on page 96 it is not making sense how to multiply thoes. Here is the problem: (-4)(-7)(3/7)
what are real numbers? in the book all the information it gives about these "real numbers" is that all the numbers in this book are real numbers. i know mrs. leckman said that real numbers are numbers plotable on a real number line however, pi is a real number and it is not plotable on a number line so is 1/3. the only true mathmatical deffinition i have is a definition out of one of my dad's graduate school textbooks and it dosnt make sense.
I was confused here with multiplication of real numbers. I was able to multipy the real numbers, but on some of the problems, the numbers were all run together. At the time, I did not know that they were supposed to be simplified with the distrubutive property. Then, after I simplfied, I solved the problem both ways, and came up with two different answers. I dont know if I multiplied or added wrong, or if I just simplified wrong... An example is (3*5)(-7)(-65*2)What would I do here?-A.L.
D.M. I need help claifying something. When you have exponents in a multiplcation problem, such as -3 to the fourth power, the answer will be positive right? I want to make sure that if you're finding the answer to a problem and when the exponent is even, though the number is a negative, it will always turn out to be a positive number.
If you are given 5(-a)(-a)(-a), the first step is to combine like terms. -a x -a is positive a squared, because a x a is a squared and two negatives cancel. Then the equation becomes 5(a^2)(-a). Then you take a^2 and x by -a, to get -a^3. Your equation becomes 5(-a^3). Depending on x, you can further solve the equation.
real numbers like you and ms leckman said are numbers that can be plotted on a number line, which means they cannot be like pi. numbers that are real numbers terminate. pi is a nonterminating number which makes it impossible to plot on a line plot. also, a number that has a decimal that repeats for ever is not a real number because you cannot exactly plot those types of numbers.
iw to dm if u hav a negative number then hav it at an exponent were the exsponent is even the answer will be postive...odd exponent and negative number = a negative answer iw to dm
There is an easy rule to remember, when multiplying to negatives syou will always get a positive, its the same rule for dividing two negative numbers, also, when adding two negative numbers you will always get aa negative, now when subtracting a negative by a negative it depends, if the negative you are subtracting from is smaler then the number you are taking away, its a positive
DG Hey guys! I don't have a problem with multiplying real numbers, but I have trouble with writing expressions for real life problems in this chapter. An example that I was struggling with was on our homework last week on 2.5 #34. This was the question: There is a slow leak in your bike tire. It is losing at a rate of 2.6 pounds per square inch per day. Let x represent the amount of air in the tire right now. Write an expression for the amount of air in the tire after 3 days. If the amount of air in the tire is now 74.5 pounds per square inch, find the amount of air in the tire after 3 days. Can someone please show me step by step how to write an expression for this particular situation? Thnx guys! :D
11 comments:
d.c.
is this chapter i have trouble simplifing the variable expression. for example if it gives you 5(-a)(-a)(-a) i am not sure what the steps for this is.
J.B
The other problem i have stuggled with is adding sutracting, multiplying and dividing negitive integers. Like in problem #27 on page 96 it is not making sense how to multiply thoes. Here is the problem:
(-4)(-7)(3/7)
CVDV
real numbers
what are real numbers? in the book all the information it gives about these "real numbers" is that all the numbers in this book are real numbers. i know mrs. leckman said that real numbers are numbers plotable on a real number line however, pi is a real number and it is not plotable on a number line so is 1/3. the only true mathmatical deffinition i have is a definition out of one of my dad's graduate school textbooks and it dosnt make sense.
RW
Im having trouble with multiplication of fractions. i just dont really remember most of it because i forgot.
I was confused here with multiplication of real numbers. I was able to multipy the real numbers, but on some of the problems, the numbers were all run together. At the time, I did not know that they were supposed to be simplified with the distrubutive
property. Then, after I simplfied, I solved the problem both ways, and came up with two different answers. I dont know if I multiplied or added wrong, or if I just simplified wrong...
An example is (3*5)(-7)(-65*2)What would I do here?-A.L.
D.M.
I need help claifying something. When you have exponents in a multiplcation problem, such as -3 to the fourth power, the answer will be positive right? I want to make sure that if you're finding the answer to a problem and when the exponent is even, though the number is a negative, it will always turn out to be a positive number.
A.H.
to D.C.
If you are given 5(-a)(-a)(-a), the first step is to combine like terms. -a x -a is positive a squared, because a x a is a squared and two negatives cancel. Then the equation becomes 5(a^2)(-a). Then you take a^2 and x by -a, to get -a^3. Your equation becomes 5(-a^3). Depending on x, you can further solve the equation.
E. Mu. to CVDV
real numbers like you and ms leckman said are numbers that can be plotted on a number line, which means they cannot be like pi. numbers that are real numbers terminate. pi is a nonterminating number which makes it impossible to plot on a line plot. also, a number that has a decimal that repeats for ever is not a real number because you cannot exactly plot those types of numbers.
iw to dm
if u hav a negative number then hav it at an exponent were the exsponent is even the answer will be postive...odd exponent and negative number = a negative answer
iw to dm
E.H To J.B.
There is an easy rule to remember, when multiplying to negatives syou will always get a positive, its the same rule for dividing two negative numbers, also, when adding two negative numbers you will always get aa negative, now when subtracting a negative by a negative it depends, if the negative you are subtracting from is smaler then the number you are taking away, its a positive
DG
Hey guys! I don't have a problem with multiplying real numbers, but I have trouble with writing expressions for real life problems in this chapter.
An example that I was struggling with was on our homework last week on 2.5 #34.
This was the question:
There is a slow leak in your bike tire. It is losing at a rate of 2.6 pounds per square inch per day. Let x represent the amount of air in the tire right now. Write an expression for the amount of air in the tire after 3 days. If the amount of air in the tire is now 74.5 pounds per square inch, find the amount of air in the tire after 3 days.
Can someone please show me step by step how to write an expression for this particular situation?
Thnx guys! :D
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